Question

V
X
27. Calculate the concentration of nitric
acid (HNO3) in moles per litre in a sample which has
a density of 1.41 gm/ml and mass percent of nitric
acid in it being 69%.( H=1 N=14 O=16)
В І О Н ТА
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Answer 1

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Answer

The density of the solution is 1.41 g/mL.

1000 g of the solution will have a volume =

Density

Mass

=

1.41

1000

=709 ml.

The mass per cent of nitric acid is 69%.

1000 g of the solution will have 1000×

100

69

=690 g of nitric acid.

The molarity of solution is

Molar mass of nitric acid ×Volume of solution

Mass of nitric acid

=

63×709

690

=0.0155 M.

Hope it helps you........

Explanation:

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