Question

How many electrons are required to make a negative charge of 5 Coulomb ?

Answer 1

Answer:

hope it will help you:-)

Answer 2

Number of electrons = 3.125 $\times 10^-^1^9$

Given:

Negative charge of 5 Coulomb.

To find:

How many electrons are required to make a negative charge of 5 Coulomb.

Formula used:

Charge = n ×e

n= number of electrons.

e= The amount of charge it carries is 1.6 $\times 10^-^1^9$ C.

Explanation:

One coulomb is the fundamental SI unit of charge. It is defined as the charge in one Ampere of current passed for one second.

Given that    charge = 5 Coulomb.

                     e= The amount of charge it carries is 1.6 $\times 10^-^1^9$   C

Charge = n ×e

         n = $\frac{Charge}{e}$ = $\frac{5}{1.6\times 10^-^1^9}$

         n = 3.125 $\times 10^-^1^9$

Number of electrons = 3.125 $\times 10^-^1^9$

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