Question

How many electrons maximum can have n+l=4 in an atom?

Answer 1

Hey there!

Given,

n + l = 4

where,

l = angular momentum quantum number

n = Principle quantum number

From Energy level of electrons we know,

l ≤ n - 1

Satisfying this condition,

The values of n and l will be 3,1 and 4,0 respectively.

Now:

Case I:

n = 3

l = 1

so, here these represents 3p subshell.

Hence, maximum no. of electrons = 6

Case II:

n = 4

l = 0

so, here these represents 4s subshell.

Hence, maximum no. of electrons = 2.

Therefore, from case I and II:

Total no. of electrons = 6 + 2 = 8

We know,

Electrons with same pin = 8 / 2 = 4.

Hope It Helps You!

Answer 2

4 is the the maximum number of electrons in an n+l=4 atom.

Both 4s (n = 4, l = 0) and 3s (n = 3, l = 1) orbitals in an atom can have n+l=4.

where,

l = angular momentum quantum number

n = Principle quantum number

If n = 3,

l = 1

As a result, these are the 3p subshells.

Thus, the maximum number of electrons is 6.

If n = 4

l = 0

As a result, they are the 4s subshells.

Thus, the maximum number of electrons is 2.

∴ from the two cases we can conclude that,

the total number of electrons = 6 + 2 = 8.

We also know that,

They can only have eight electrons because four orbitals are involved. Half of the electrons (i.e,4) can have the same spin (+1/2 or -1/2) among them.

i.e, Electrons with same pin = $\frac{8}{2}$ = 4

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