Question

How many electrons must be added to a charge
body with magnitude 36 X 10 -18C
doi​

Answer 1

Answer:

if you have read the newsletter try to solve this also yourself

Answer 2

To find:

Number of electrons that must be added to a neutral body to gain a charge of -36 × 10^(-18) C?

Calculation:

Let the total number of electrons to be added be "n":

Now , we know that the total charge gained by the body will be equal to the product of charge of electron multiplied by the total number of electrons

$\therefore \: q = n \times e$

$= > \: - 36 \times {10}^{ - 18} = n \times ( - 1.6 \times {10}^{ - 19} )$

$= > \: n = \dfrac{ - 36 \times {10}^{ - 18} }{ - 1.6 \times {10}^{ - 19} }$

$= > \: n = \dfrac{ 36 \times {10}^{ - 18} }{ 1.6 \times {10}^{ - 19} }$

$= > \: n = 22.5 \times {10}^{ - 18 + 19}$

$= > \: n = 22.5 \times {10}^{1}$

$= > \: n = 22.5 \times 10$

$= > \: n = 225 \: electrons$

So, 225 electrons have to be added to gain the required charge on the body.

HOPE IT HELPS.