How many electrons must be removed from a coin to leave it with a charge of +1.10^-7 C?
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Explanation:
625 billion electrons should be removed from [neutral] coin.
Answered by
1
Answer:
Q = ne
Here
- Q = charge
- n = number of electrons
- e = charge of 1 electron
Charge of 1 electron = 1.6 × 10^-19 Coulomb
Number of electrons = 10^-7 Coulomb / (1.6 × 10^-19 Coulomb)
= 625 × 10^9 electrons
= 625 billion electrons
625 billion electrons should be removed from [neutral] coin.
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