Question

How many electrons per second flow through a filament of 120 V and 60 W electric bulb? Given electric power is the product of voltage and current.

Answer 1

Given,

Electric Potential on filament = V = 120 V

Power of electric bulb = P = 60 W

Time  taken = T= 1s

As we know,

P = VI

From the above we get value of I,

I = $\frac{P}{V}$ = $\frac{60}{120}$ = 0.5 A

As per the question , we need to calculate number of electrons(n),

Formula used ,

 n = $\frac{It}{e}$

On putting the values ,

N = $\frac{0.5*1}{1.6*10^{-19}}$

    = $3.125*10^{18}$

Answer 2

I = POWER / TIME = 0.5 A

No. Of electrons per unit time equal

Current per unit charge

= n = i.t / e

E is the charge on electron

Answer = 3.125 ✖ 10 Rais to power 18

Hope it helps you

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