How many electrons should be removed from a coin of mass 1.6g so that it may float in an electric field of intensity 10 to the power of 9 N /C directed upward
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Given,
Mass= 1.6g
take acceleration due to gravity = g= 10 m/s²
from the relation of electric field and force i.e F= E.q
∵F= m.g (newton's law)
∴M. g = E. q
1.6g x 10 m/s² = 9 N/C x q
⇒ q= ne (n= no of electrons, e= charge on an electron= -1.6x10∧-19 C)
⇒1.6 x 10 ÷ 9= ne
⇒1.6 x 10 / 9 x 1.6 x 10∧-19=n
n= 1.77778x 10^19
Mass= 1.6g
take acceleration due to gravity = g= 10 m/s²
from the relation of electric field and force i.e F= E.q
∵F= m.g (newton's law)
∴M. g = E. q
1.6g x 10 m/s² = 9 N/C x q
⇒ q= ne (n= no of electrons, e= charge on an electron= -1.6x10∧-19 C)
⇒1.6 x 10 ÷ 9= ne
⇒1.6 x 10 / 9 x 1.6 x 10∧-19=n
n= 1.77778x 10^19
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