Physics, asked by Simmi1999, 1 year ago

How many electrons should be removed from a coin of mass 1.6g so that it may float in an electric field of intensity 10 to the power of 9 N /C directed upward

Answers

Answered by jayantkumar46086
0

Answer:

Here, F=mg=neE where q=ne, E is the electric field.

So, n=

eE

mg

=

(1.6×10

−19

)(10

9

)

(1.6×10

−3

)(9.8)

=9.8×10

7

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