Question

How many electrons should be removed from a coin of mass 1.6g so that it may float in an electric field of intensity 10 to the power of 9 N /C directed upward

Answer 1

Answer:

Here, F=mg=neE where q=ne, E is the electric field.

So, n=

eE

mg

=

(1.6×10

−19

)(10

9

)

(1.6×10

−3

)(9.8)

=9.8×10

7