How many electrons will weigh 1 gram ?
Answers
Answered by
66
weight of electron= 9.1 x 10^ -28 g
let no of electrons = N
N × 9.1 × 10^-28 g = 1 g
N = 1/9.1 x 10^-28 = 1/9.1 x 10^28
= 1.1 x 10^27 ( approximately)
let no of electrons = N
N × 9.1 × 10^-28 g = 1 g
N = 1/9.1 x 10^-28 = 1/9.1 x 10^28
= 1.1 x 10^27 ( approximately)
Answered by
28
Answer:
Mass of an electron = 9.1 x 10-28 g
9.1 x 10-28 g contains = 1 electron
Therefore 1g contains = 1/9.1 x 10-28 *1 = 1.098 x 1027 electrons
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