Question

how many electrons would have to be removed from A copper penny to leave it with the positive charge of 10 to the power minus 7 C

Answer 1

Hii
10-7 = n|e|

10-7 = n * 1.6 *10-19
n= 0.625* 1012 electrons
this is the answer... Hope it helps..

Answer 2

Answer:

0.625*10^12

Explanation:

The charge on 1 proton =1.6*10^19C

The charge on 1 electron =-1.6*10^-19C

A neutral object has no charge because it contains an equal amount of protons (+) and electrons(-).

If we remove N electrons , the object now has N more electrons.So, the object's charge is N*(1.6*10^-19)C

So, N*(1.6*10^-19)=10^-7

N=10^-7/(1.6*10^-19)

N=0.625*10^12(ans)

Note - Here,'*' symbolizes multiplied to.