How many four digit even numbers are possible by using the digits 0 1 2 3 5?
Answers
Answered by
0
If 0 is kept in last place
Then we have 4 no. in 1st digit
3 in 2nd
2 in 3rd
Total no. = 4×3×2×1 = 24
If 2 is used in last place then
We have 3 no. in 1st digit (as 0 can't come)
3 in 2nd (as 0 can come)
2 in 3rd
Total no. = 3×3×2×1 = 18
Ans = 18+24 = 42
Then we have 4 no. in 1st digit
3 in 2nd
2 in 3rd
Total no. = 4×3×2×1 = 24
If 2 is used in last place then
We have 3 no. in 1st digit (as 0 can't come)
3 in 2nd (as 0 can come)
2 in 3rd
Total no. = 3×3×2×1 = 18
Ans = 18+24 = 42
Similar questions