How many four digit numbers divisible by 5 can be formed with the digits 0,1,2,3,4,5, and 6?
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Answer:
588 if the digits are repeating
Step-by-step explanation:
for repeating case:
_ _ _ _
the fourth place can consist of either 0 or 5,
as we have to find the multiple of 5 so there are only two possibilities at fourth place
now in the first place out of seven only six numbers can come because if we put 0 then it will be 3 digit number
6 × 7 × 7 × 2 = 588
Hence there will be total 588 numbers that can be formed
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