How many four digit numbers divisible by twenty nine have the sum of their digits 29?
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Simple way to find these would be to use Excel. The final numbers are 4988, 7598, 7859, 9686, 9947.
Column 1 - numbers 35 to 344 (These are the numbers between which multiples of 29 are 4 digit numbers).
Column 2 - 29 * numbers from column1 = all the 4 digit multiples of 29
Column 3 - Units digit = mod(multiple,10)
Column 4 - Tens digit = {mod(multiple,100)-mod(multiple,10)}/10
Column 5 - Hundreds digit = {mod(multiple,1000)-mod(multiple,100)}/100
Column 6 - Thousands digit = {mod(multiple,10000)-mod(multiple,1000)}/1000
Column 7 = Sum of digits = sum of columns 3 to 6
With a simple conditional formatting of column 7, we get these 5 numbers which satisfy the required condition.
Hope it helps.
Column 1 - numbers 35 to 344 (These are the numbers between which multiples of 29 are 4 digit numbers).
Column 2 - 29 * numbers from column1 = all the 4 digit multiples of 29
Column 3 - Units digit = mod(multiple,10)
Column 4 - Tens digit = {mod(multiple,100)-mod(multiple,10)}/10
Column 5 - Hundreds digit = {mod(multiple,1000)-mod(multiple,100)}/100
Column 6 - Thousands digit = {mod(multiple,10000)-mod(multiple,1000)}/1000
Column 7 = Sum of digits = sum of columns 3 to 6
With a simple conditional formatting of column 7, we get these 5 numbers which satisfy the required condition.
Hope it helps.
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