Math, asked by Bhavyanayak, 4 months ago

How many four digit odd numbers can be formed using digits 1 to 9 without repetition ?​

Answers

Answered by nikhil8239
0

Answer:

given: there are total of 10 digits (0,1,2,3,4,5,6,7,8,9), and odd numbers cannot have an even units digit, so there are 5 digits/choices (1,3,5,7,9). total four-digit odd integers with different digits: 5*8*8*7=35*64=2240.

Step-by-step explanation:

Answered by kim3527
0
there are total of 10 digits (0,1,2,3,4,5,6,7,8,9), and odd numbers cannot have an even units digit, so there are 5 digits/choices (1,3,5,7,9). total four-digit odd integers with different digits: 5*8*8*7=35*64=2240.



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