Math, asked by sushank9041, 11 months ago

How many four digits number can be formed with the digits 3,5,7,8,9 which are greater then 7000 if repetition of digits are not allowed?

Answers

Answered by Devanju2003
6

Answer:

Step-by-step explanation:

Being greater than 7000 means it must start with 7,8 or 9. So we have 3 options here.

For the second digit we have 4 options, because we can’t repeat the one we used as first digit.

For the third digit we have 3 options.

And for the last digit we have 2 options.

So, we have a total of 3×4×3×2=72 numbers of four digits.

Answered by Anonymous
4

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Given,

" Repetition of given digits is not allowed "

Thus,

The first place can be filled in 3 ways by anyone of 7 , 8 and 9 digits

The second palce can be filled in 4 ways by anyone of the remaining digits

The third palce can be filled in 3 ways by anyone of the remaining digits

The fourth palce can be filled in 2 ways by anyone of the remaining digits

By multiplication principle , we get

Number of four digits numbers greater than 7000 = 3 × 4 × 3 × 2 i.e 72 ways

Hence , the required number of four digits numbers which are greater than 7000 is 72

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