How many geometrical (cis-trans) isomers are there of hex-2,4-diene, ch3ch=chch=chch3?
Answers
The answer will be 3 as (Cis Cis, Trans -Trans and the 3rd one is Cis-Trans or trans -Cis ( exactly same as molecule is symmetrical, means name is unchanged if we start numbering from left side or right side of molecule it was trick. Normally we use formula n2(power of n is 2) but it cannot be used for one C double bond and C atom having pi bond attach with similar groups ( we studied that no cis-trans) or for such molecules. So In this question correct answer would be 3.
Explanation:
CH3-CH=CH-CH=CH-CH. FIND BY THE FORMULA OF FINDING NO. OF GEOMETRICAL ISOMER IN A ORGANIC COMPOUND. HERE...
ENDS OF GEOMETRICAL ISOMER IS EQUAL
NO. OF DOUBLE BONDS ARE =n=2
Here the value of N is even
Then find no. Of P=n/2 = 2/2=1
:value of P=1
Then....
2^(n-1) + 2^(p-1) =2^(2-1) + 2^(1-1)
= 2^1 + 2^0
=2 + 1
=3
GI = 3