Question

two coins are tossed 1000 times and the outcome are recorded as below number of heads=0 frequency =250number of heads=1 frequency=500number of heads= 2 frequency= 200based on the information the probability for the most one head is (A) 1/15 (B) 1/4 (C) 4/5 (D)3/4explain your answer plz

Answer 1

Answer:

Step-by-step explanation:

It's 3/4

Because H frequencies are

0=250

1=500

2=200

So 250+500+200=950

So total is 950

Now 250 is for 0 frequency means nothing attempt

So 950-250=700

P(E)=700/950=14/19

Now subtract 19-3 because there are 3 frequencies.

So P(E)=14/19-3=14/16=3/4