Question

How many gm of HCL is needed for complete reaction with 69.6 gm MnO2.

Answer 1

hey mate❤️❤️❤️❤️❤️❤️



"Mass of MnO2 = 54.94 gm

So, MnO2 + 4HCL  MnCl2 + Cl2 + 2H2O

So, 1 mole of MnO2  4 moles of HCL

 86.94 gm  4x36.5 gm

 69.6 gm  4x36.5/86.94 gm

=1.679 gm

So, here is the answer. 1.679 gm of gm of HCL is needed for complete reaction with 69.6 gm MnO2

"

✌️✌️✌️PLS MARK BRAINLIEST✌️✌️

Answer 2

Explanation:

ans 116.8