How many gm of HCL is needed for complete reaction with 69.6 gm MnO2.
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Answered by
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hey mate❤️❤️❤️❤️❤️❤️
"Mass of MnO2 = 54.94 gm
So, MnO2 + 4HCL MnCl2 + Cl2 + 2H2O
So, 1 mole of MnO2 4 moles of HCL
86.94 gm 4x36.5 gm
69.6 gm 4x36.5/86.94 gm
=1.679 gm
So, here is the answer. 1.679 gm of gm of HCL is needed for complete reaction with 69.6 gm MnO2
"
✌️✌️✌️PLS MARK BRAINLIEST✌️✌️
"Mass of MnO2 = 54.94 gm
So, MnO2 + 4HCL MnCl2 + Cl2 + 2H2O
So, 1 mole of MnO2 4 moles of HCL
86.94 gm 4x36.5 gm
69.6 gm 4x36.5/86.94 gm
=1.679 gm
So, here is the answer. 1.679 gm of gm of HCL is needed for complete reaction with 69.6 gm MnO2
"
✌️✌️✌️PLS MARK BRAINLIEST✌️✌️
Answered by
2
Explanation:
ans 116.8
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