How many gm of K2Cr2O7 is present in 1L N/10solution in acidic medium
Answers
Answered by
1
In Acidic medium, This Mn+7 goes to Mn+2 state and hence there is a net gain of 5 electrons. so, eq wt = 158/5 = 31.6 g. Hence, eq wt = 158/3 = 52.67g. In many cases though if it's written alkaline, it mostly means the neutral one; for the highly alkaline thing, it'll especially mention it.
Answered by
1
Answer:
it is known when it is in acidic mentor ending gm of K2 cr2 O7 is present in one litre of 10 solution in acidic medium
Similar questions