Question

how many gram of Acetic Acid are present in 500 ml of its 0.5M aqueous solution

Answer 1

hey frnd,nice question,

acetic acid=CH3COOH

molar mass of CH3COOH=12+3+12+16+16+1
=60g

$molarity = \frac{mass}{molar \: mass} \times \frac{1000}{volume(ml)}$

$0.5 = \frac{mass}{60} \times \frac{1000}{500}$

$0.5 = \frac{mass}{60} \times 2$

$0.5 = \frac{mass}{30}$

$mass = 0.5 \times 30 \\ mass = 15$

So,15 g of acetic acid are present in 500ml of its 0.5M solutions

plzzz mark as brainliest if it helps u