Question

How many gram of H2SO4 are contained in 0.05L of 0.5 M solution?

Answer 1

Answer: 2.45 grams

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

$Molarity=\frac{moles}{\text {Volume in L}}$

$0.5M=\frac{moles}{\text {0.05L}}$

moles of $H_2SO_4=0.025moles$

Mass of $H_2SO_4=moles\times {\text {molar mass}}=0.025moles\times 98grams/mol=2.45grams$

Thus 2.45 grams of  $H_2SO_4$ are contained in 0.05 L of 0.5 M solution.