how many gram of NaCl are required to prepare 100 ml of solutions of 1 M NaCl?
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let's the weight be w
M=number of mole of solute/volume (in ml)
1=w/58.5*100
w=5.85*100/1000
=5.85
M=number of mole of solute/volume (in ml)
1=w/58.5*100
w=5.85*100/1000
=5.85
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