Question

How many gram of water will be obtained on reacting 64 g of oxygen gas with enough hydrogen gas to form water

Answer 1

Answer:

2H20+O2---->2H20

1 mol o2 makes 2 moles h2o

moles of o2 = givenweight/molar mass =64/16 = 4moles

1 mole o2 makes - 2 moles water

therefore 4 moles will make 8 moles water

weight of water = moles x molar mass = 8 x 18 = 144gm

Pls mark this as brainliest

Answer 2

answer is 36 g

32 g of oxygen react to form 18 g of water

so 64 g of oxygen rect to form 32g of water