Math, asked by anupamclashanu, 8 months ago

How many grams are present in 5.6 litres of CO2 at N.T.P​

Answers

Answered by Itzraisingstar
1

Answer:

Step-by-step explanation:

At STP, 5.6 L of carbon dioxide corresponds to 0.25 moles. They will be obtained from 0.25 moles of calcium carbonate. 0.25 moles of calcium carbonate (molecular weight 100 g/mole) corresponds to 25 g.

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Answered by rekhay934
1

Answer:

At STP, 5.6 L of carbon dioxide corresponds to 0.25 moles. They will be obtained from 0.25 moles of calcium carbonate. 0.25 moles of calcium carbonate (molecular weight 100 g/mole) corresponds to 25 g.

Step-by-step explanation:

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