Question

How many grams are there in 7.40 moles of AgNO3?

Answer 1

Answer:

The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles AgNO3, or 169.8731 grams.

Explanation:

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Answer 2

Given: 7.40 moles of AgNO3

To find: number of grams of AgNO3

Solution: We are given moles of AgNO3 that is called silver nitrate

we need to find the mass of AgNO3 that is present in its 7.4 moles

the formula going to use here is

n = m/M

here n is number of moles of the substance, m is mass present of that substance, M is the molecular mass of that substance

here we are given n of AgNO3 and we know the molecular mass of AgNO3 that is 169.87

on putting values we will get

m = 7.4×169.87 = 1257.04

m = 1257.04 g

Therefore, number of grams of AgNO3 present in its 7.4 moles is 1257.05g.