Question

How
many grams of 02 is required
for
combustion of 480 gram of Mg?
Find the mass of Mgo
formed in the reaction?
​

Answer 1

Answer:

320,gm O2. 800gmMgO

Explanation:

2Mg+O2----------> 2MgO

Moles of Mg = 480/24 =20

Moles of O2 req = 20/2 =10 =10*32 =320gm

Moles of MgO produce= 20 +20*40 =800gm