Question

How many grams of C4O3H10 contain 5.860 x 1025 atoms of hydrogen?

Answer 1

Answer: The mass of the given compound containing given amount of hydrogen atoms is 1032.6 grams.

Explanation:

We are given a chemical compound having chemical formula $C_4O_3H_{10}$

We know that:

Mass of $C_4O_3H_{10}$ = 106.12 g/mol

This compound contains 4 moles of carbon atom, 3 moles of oxygen atom and 10 moles of hydrogen atom

According to mole concept:

1 mole of an element or compound contains $6.022\time 10^{23}$  number of particles.

So, 1 mole of given compound contains = $10\times 6.022\times 10^{23}=6.022\times 10^{24}$ number of hydrogen atoms.

We are given:

Number of hydrogen atoms = $5.860\times 10^{25}$

Calculating the mass of compound for given number of hydrogen atoms:

When $6.022\times 10^{24}$ number of hydrogen atoms are present, the mass of compound is 106.12 grams

So, when $5.860\times 10^{25}$ number of hydrogen atoms are present, the mass of compound will be = $\frac{106.12}{6.022\times 10^{24}}\times 5.860\times 10^{25}=1032.6g$

Hence, the mass of the given compound containing given amount of hydrogen atoms is 1032.6 grams.