Reaction between sulphur and hot concentrated nitric acid
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Heyy mate ❤✌✌❤
Here's your Answer...
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S + 6HNO3 ---------- 2H2O + H2SO4 + 6NO2.
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Here's your Answer...
⤵️⤵️⤵️⤵️⤵️⤵️⤵️⤵️
S + 6HNO3 ---------- 2H2O + H2SO4 + 6NO2.
✔✔✔
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Answered by
2
S + 6 HNO3 > H2SO4 + 6 NO2 +2 H2O
Sulphur gets oxidized to Sulphuric acid and nitrogen dioxide is produced.
As sulphur exists as S8 rings, equation can be written as
S8 + 48 HNO3 > 8 H2SO4 + 48 NO2 + 16 H20
Sulphur gets oxidized to Sulphuric acid and nitrogen dioxide is produced.
As sulphur exists as S8 rings, equation can be written as
S8 + 48 HNO3 > 8 H2SO4 + 48 NO2 + 16 H20
i hope help u
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