Question

how many grams of cane sugar are present in 534.2 g of aqueous solution having molality 0.2​

Answer 1

Answer:

Molality can be defined as "Total moles of a solute present in one kilogram of a solvent." The terms need, thus, to calculate molality are Moles of solute and the mass of solvent in kilograms.

dissolving one gram of the solute in 1000 grams of solvent, will be called as 1 molal solution or 1m solution

Formula :

Molality = Number of moles of solute / Mass of solvent in kilograms

THEREFORE, Ans will be

Molality= [0.1/500]*1000

Molality =0.2