Question

how many grams of CaWO4 would contain the same of tungesten that is present in 569 gm of FeWO4 ​

Answer 1

Answer:

Let the mass of CaWO

4

be w g. As given,

Mass of W in w g of CaWO

4

= mass of W in 569g of FeWO

4

Moles of W in CaWO

4

×at. mass of W = Moles of W in FeWO

4

× at. mass of W

As both CaWO

4

and FeWO

4

contains 1 atom of W each,

∴ moles of CaWO

4

× at. mass of W = Moles of FeWO

4

× at. mass of W

=

288

w

×184 = (569/304)×184

= W=539.05g.

Explanation:

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