How many grams of chlorine are required to completely react with 0.40g of hydrogen to yield hydrochloric acid ? Also calculate the amount of hydrocloric acid formed.
Answers
Answered by
114
The reaction is as follow:
H2 + Cl2---------> 2HCl
The mole ratio is 1:1:2
Moles of 0.4g hydrogen.... moles = mass/molar mass 0.4/2=0.2 moles
mole ratio is 1:1,the the moles of chlorine required will be 0.2 moles
mass of chlorine required
mass= moles x molar mass.....moles=0.2 molar mass= 35.5
mass=0.2 x 35.5
= 7.1 g
Mass of Hcl formed
Since mole ratio H2: HCl = 1:2
Moles of H2 is 0.2moles , hence moles of HCl = 0.4 moles
Molar mass of HCl = 36.5 (mass = moles x molar mass)
mass= 0.4 x 36.5
= 14.6g
Mass of chlorine formed= 14.6 grams
H2 + Cl2---------> 2HCl
The mole ratio is 1:1:2
Moles of 0.4g hydrogen.... moles = mass/molar mass 0.4/2=0.2 moles
mole ratio is 1:1,the the moles of chlorine required will be 0.2 moles
mass of chlorine required
mass= moles x molar mass.....moles=0.2 molar mass= 35.5
mass=0.2 x 35.5
= 7.1 g
Mass of Hcl formed
Since mole ratio H2: HCl = 1:2
Moles of H2 is 0.2moles , hence moles of HCl = 0.4 moles
Molar mass of HCl = 36.5 (mass = moles x molar mass)
mass= 0.4 x 36.5
= 14.6g
Mass of chlorine formed= 14.6 grams
Answered by
7
Answer:
14.6
Explanation:
Answer is correct
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