Question

How many grams of Cl2 can be prepared from the reaction of 16.0 g of MnO2 and 30.0 g of HCl according to the following chemical equation?

MnO2 + 4HCl --> MnCl2 + Cl2 + 2H2O

Answer 1

Answer:

Explanation:

moles of mno2=0.134

moles of hcl = 1.764

equivalent of limiting reagent = equivalent of product formed

moles*f=moles*f

0.134*2 = moles*2

moles=0.134

w/71=0.134

w=9.514

Answer 2

Answer:13 g

Explanation: here mno2 is the limiting reagent so run will proceed with respect to mno2

If 87 g of mno2 gives 71 gram of ca+2 then 16 gram will give 13g of cl2