Question

How many grams of common salt (NaCl) will be formed when 11.5gm of sodium (Na) reacts with 35.5gm of chlorine gas(Cl2)? Atomic weight of sodium is 23 and that of chlorine gas is 71​

Answer 1

Explanation:

Mass of Na is divided with its atomic mass to obtain number of moles.

Number of moles of Na =

23

1.15

=0.05 moles.

Na

+

+e

−

→Na

Thus, deposition of 1 mole of Na will require 1 mole of electrons which corresponds to 1 Faraday of electricity. The, deposition of 0.05 moles (1.15 g) of Na will require 0.05 moles of electrons which corresponds to 0.05 Faraday of electricity.