Question

How many grams of concentrated nitric acid solution
should be used to prepare 250 mL of 2 M HNO,?
The concentrated acid is 70% (w/w) HNO,​

Answer 1

No. of moles = (250×1000)/2

= 0.5 moles

No. of moles = molarity × volume

Requird mass of HNO3 = 0.5 × 63

= 31.5 gm

70 gm of HNO3 are present in 100 gm of solution,

So 1 gm will be present in 100/70 gm of solution.

31.5 gm be present in (100/70)× 31.5 gm of solution

= 45 gm