How many grams of copper will be present in 1.61 x 10 atoms of copper
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Answer:
Explanation:
one atom of copper weighs 29u.
One mole of copper is 29g.
6.022*10^23 copper atoms weigh 29g
no. of copper atoms which weigh 1.61g=(1.61/29)*6.022*10^23
= 3.312* 10^23 copper atoms
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