Question

How many grams of ferrous sulfide will be produced by mixing 4 grams of iron and 4 grams of sulfur?​

Answer 1

Explanation:

Molar mass of Fe = 56 g/mol

Molar mass of S = 32 g/mol

Molar mass of FeS = (56 + 32) g/mol = 88 g/mol

Initial moles of Fe = (56 g) / (56 g/mol) = 1 mol

Initial moles of S = (40 g) / (32 g/mol) = 1.25 mol

Balanced equation for the reaction:

Fe + S → FeS

Mole ratio F : S : FeS = 1 : 1 : 1

Since (Initial moles of Fe) < (Initial moles of S), Fe is the limiting reactant.

Moles of Fe reacted = 1 mol

Moles of FeS formed = 1 mol

Mass of FeS formed = (1 mol) × (88 g/mol) = 88 g