How many grams of glucose (C6H12O6) is needed to make a 0.93 molar solution in 165mL of water?
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molarity= no of moles/volume in L
=(no of moles/volume in ml)×1000
finding no of moles,
no of moles=given mass/molar mass
let given mass be x g.
molar mass of glucose is 6(12)+12(1)+6(16)= 180g
no of moles= x/180
0.93=(x/180)×1000/165 in ml
(0.93× 165)/1000= x/180
153.45×170/1000= x
therefore, x=27.62 g of glucose is needed to make a 0.93 molar solution in 165 ml of water.
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