Question

how many grams of gold can be recovered from 45.00 g of gold (ii) chloride?

Answer 1

Answer:

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Answer 2

The answer is 28.8 grams

GIVEN

Weight of gold(iii) chloride = 45.00 grams

TO FIND

Amount of gold recovered.

SOLUTION

The above problem can be simply solved as follows.

Molecular mass of Au₂Cl₆ = 606.5 g/mol

Molar mass of Gold (Au) = 197 grams

Amount of Au in 606.5 g/mol = 197 × 2 = 394 grams

Amount of gold in 1 grams of Au₂Cl₆ = 394/606.5 = 0.64 grams

Amount of Gold recovered from 45 grams of gold(iii) chloride = 45 × 0.64 = 28.8 grams

Hence, The answer is 28.8 grams

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