How many grams of h3po4 is required to completely neutralize 120g of naoh?
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Answered by
12
Hi there,
Given
● NaOH sample mass = 120g
● Molar mass of NaOH = 40
☆ So, NaOH moles = 120÷40= 3mol
◇ Neutralization equation
3NaOH + H3PO4 = 3H2O + Na3PO4
¤ na moles of acid
¤ nb moles of base
¤ a,b are coeficientes from the equation
◇ for acid n.a ÷ a = n.b ÷ b for base
na÷ 1 = 3÷ 3
■ So number of moles of acid = 1 mole
■ Mass of one mole = 98 gm
☆ so, the mass required to complete neutralization is 98 gm
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Answered by
0
Answer:98
Explanation: 98g
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