How many grams of hydrogen chloride,HCL are required to prepare 4 Litre of 5M HCL in water?
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730 grams of hydrogen chloride are required to prepare 4 Litre of 5M HCL in water
Given:
Molarity of HCl = 5M
Volume of HCl = 4liters
To find:
Grams of hydrogen chloride are required to prepare 4 Litre of 5M HCL in water
Solution:
We have a formula
Moles = Molarity × Volume
Thus,
Moles of HCl = 5 × 4
= 20 moles
Now, the Atomic weight of HCl = 1+35.5
= 36.5
Now, Calculate the total grams of HCl
Total grams = Moles × Atomic weight
= 20 × 36.5
= 730 grams
Therefore, 730 grams of hydrogen chloride are required to prepare 4 Litre of 5M HCL in water
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