Question

How many grams of Hydrogen (H) would need to react with 190 grams of Fluorine (F) to make 200 grams of HF (Hydrofluoric Acid)?

Answer 1

hi friend,

Following is the answer,

Mol weight of HF = 1 + 19 = 20 g/mol HF

200 g HF * ( 1 mol / 20 g HF) = 10 mol HF

The stoichiometry is 1:1 for H:F

So you need; 10 mol H & 10 mol F

mol weight of H = 1 g/mol

10 mol H * (1 g/mol) = 10 g H

therefore 10 grams of hydrogen is required to react with 190 gram of flourine to make 200 gram of hydrofluoric acid.