how many grams of KCl must be added to 75g of water produce a solution that is 2.25 molal
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Answer:
12.57 g of KCl
Explanation:
molality = weight of KCl × 1000
/ molar mass of KCl × 75 g
H2O
= x × 1000/74.5×75 = 2.25
so, X = 12.57
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yashbantai:
thanks I'm taking given mass of kCl = 75 g that was I'm doing wrong thanks man
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plz
how can I do that
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