Question

How many grams of kcl should be added to 1 kilogram of water to lower its freezing point to8 degrees celsius?​

Answer 1

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Answer 2

Answer:

Explanation:

Since KCl dissociate in water completely L = 2

ΔTf = ikf x m;

m = ΔTf/ikf

m = 8 / 2 x 1.86 = 2.15 mol/kg.

Grams of KCl = 2.15 x 74.5 = 160.2 g/kg