How many grams of KMnO4 is required to prepare KMnO4 solution of 0.3 normal in 100 ml of water
Answers
Answer:
20
Explanation:
mark me as brainliest
Answer:
Definition:
Molarity is a measure of the concentration of a solute in a solution or of any chemical species, in terms of amount of a substance in a given volume. A commonly used unit for molar concentration used in chemistry is mol/L. A solution of concentration 1 mol/L is also denoted as 1 molar (1 M).
Molar concentration or molarity is most commonly expressed in units of moles of solute per litre of solution. For use in broader applications, it is defined as amount of solute per unit volume of solution, or per unit volume available for the species, represented by lowercase c:
c=
V
n
where,
n= no. of moles of solute.
V= volume of solution in litres.
Calculation:
Let the weight required be x g.
Molarity c=0.1 M
Number of moles of KMnO
4
is n=
158.034
x
moles
The volume of solution in litrs is V=
1000
250
=0.25 litres
Molarity of the given solution is given as c=
V
n
c=
0.25
158.034
x
=0.1
⟹x=158.034×0.1×0.25
⟹x=3.95 g
Therefore, weight of KMnO
4
required is 3.95 g.