how many grams of MnO2 required to react completely with 25 ml 0.5 M HCl.
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Answered by
3
According to the given equation:
MnO2+4HCl→MnCl2+Cl2+2H2o
1 mole of MnO2reacts with 4 mole of HCl
or 87 g MnO2reacts with 146 g HCl
∴ 5 g MnO2
Will react with
87
146
×5gHCl=8.39HCl
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Answered by
1
Answer:
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Explanation:
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