Question

how many grams of Na2S2O2 are needed to prepare 5 litre of 8% solution where density =1.075g/ml

Answer 1

1% water solutions: = 1g / 100g water = 1 / 100 = 0.01g / g water PPM Solutions 1 / 1,000,000 = 0.000001 = 1 ppm 1 gram of a 1% solution in 100 g water = 0.01g / 100g = 0.000100 = 100 ppm 0.1 gram of a 1% solution in 100 g water = 0.001g/100g = 0.000010 = 10 ppm To make a 1 ppm taste solution, add 10 grams of a 10 ppm