Question

how many grams of NaOH will be required to neutalize 12.2g benzoic acid? [C6H5COOH]​

Answer 1

Answer:

Explanation:

❤HERE IS YOUR ANSWER❤

C6H5COOH →C6H5COONa+H2O

Equivalent weight of C6H5COOH = 122gm

Equivalent weight of NaOH= 40 gm

C6H5COOH requires for complete neutralization = 40g NaOH.

Thus 12.2 g of C6H5COOH would require (40 x 12.2)/(122) = 4 gms of NaOH.

☺☺HOPE IT HELPS..☺☺

Answer 2

C6H5COOH+NaOH= C6HtOONa+H2O

C6H5COOH+NaOH= C6HtOONa+H2Ow\40= 12.2/122

C6H5COOH+NaOH= C6HtOONa+H2Ow\40= 12.2/122=4grams

hope it's help you Didi ❤