Question

How many grams of NaOH would react with 507 g FeCl2 in the reaction FeCl2 + 2NaOH Fe(OH)2(s) + 2NaCl?

Answer 1

Answer: Correct answer is 507g

FeCl2 x (1 mol FeCl2 / 126.8 g FeC2) x (1 mol Fe(OH)2 / 1 mol FeCl2) x (89.8 g Fe(OH)2/ 1 mol Fe(OH)2) = 359 g Fe(OH)2.

Answer 2

Answer: Correct answer is 507g

FeCl2 x (1 mol FeCl2 / 126.8 g FeC2) x (1 mol Fe(OH)2 / 1 mol FeCl2) x (89.8 g Fe(OH)2/ 1 mol Fe(OH)2) = 359 g Fe(OH)2.