Question

how many grams of neon will have same number of atoms as are there in 4 gram of calcium

Answer 1

in 40 g of calcium number of atoms =6.022×10^23
so in 4 g of calcium no of atoms=0.6022×10^23

to find the number of atoms in 4 g of calcium we divided avogadro number with 10


mass of neon =20
so grams of neon needed =20÷10=2 grams

Answer 2

Number of particles in 4 g of Ca,

= 4/40×6.022×10²³

= 6.022×10²² atoms

Therefore, number of atoms of Ne same as 4 g of Ca

= 20×6.022×10²²/6.022×10²³

=20/10

=2 g