Question

How many grams of neon will have the same number of atoms as 4gram of calcium

Answer 1

Molar mass of Ne = 20g

Mass of 1 atom of Ne = Molar mass/Avagadro No = 20 / 6.022*10²³ g

Molar mass of Ca = 40 g

Number of particles in 4 g of Ca = 4/40*6.022*10²³ = 6.022*10²² atoms

Therefore, number of atoms of Ne same as 4 g of Ca = 20*6.022*10²²/6.022*10²³

=20/10

=2 g

Ans: 2g of Ne has the same no of atoms as 4g of Ca.

Hope you understood it now!

Answer 2

2g answer

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